Giải câu 2 trang 42 VBT toán 5 tập 1

Bài 2: Trang 42 VBT toán 5 tập 1

Tìm :

a) + $\frac{1}{4}$ = $\frac{5}{8}$ b) - $\frac{1}{3}$ = $\frac{1}{6}$

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c) x $\frac{3}{5}$ = $\frac{9}{10}$ d) : $\frac{1}{6}$ = 18

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Bài làm:

a) + $\frac{1}{4}$ = $\frac{5}{8}$

= $\frac{5}{8}$ - $\frac{1}{4}$

= $\frac{5}{8}$ - $\frac{2}{8}$

= $\frac{3}{8}$

b) - $\frac{1}{3}$ = $\frac{1}{6}$

= $\frac{1}{6}$ + $\frac{1}{3}$

= $\frac{1}{6}$ + $\frac{2}{6}$

= $\frac{1}{4}$

c) x $\frac{3}{5}$ = $\frac{9}{10}$

= $\frac{9}{10}$ : $\frac{3}{5}$

= $\frac{9}{10}$ x $\frac{5}{3}$

= $\frac{3}{2}$

d) : $\frac{1}{6}$ = 18

= 18 x $\frac{1}{6}$

= 3