Giải bài tập 2 trang 167 sgk toán 42

Bài 2: Trang 167 - sgk toán lớp 4

Tính:

a) $\frac{2}{7} + \frac{3}{5}$ $\frac{31}{35} - \frac{2}{7}$ $\frac{31}{35} - \frac{3}{5}$ $\frac{3}{5} + \frac{2}{7}$

b) $\frac{3}{4} + \frac{1}{6}$ $\frac{11}{12} - \frac{3}{4}$ $\frac{11}{12} - \frac{1}{6}$ $\frac{1}{6} + \frac{3}{4}$

Bài làm:

$\frac{2}{7} + \frac{3}{5}= \frac{10}{35}+ \frac{21}{35}= \frac{31}{35}$

$\frac{31}{35} - \frac{2}{7}= \frac{31}{35}- \frac{10}{35}= \frac{21}{35}$

$\frac{31}{35} - \frac{3}{5}= \frac{31}{35}- \frac{21}{35}= \frac{10}{35}$

$\frac{3}{5} + \frac{2}{7}= \frac{21}{35}+ \frac{10}{35}= \frac{31}{35}$

$\frac{3}{4} + \frac{1}{6}$ $\frac{11}{12} - \frac{3}{4}$ $\frac{11}{12} - \frac{1}{6}$ $\frac{1}{6} + \frac{3}{4}$

$\frac{3}{4} + \frac{1}{6}= \frac{9}{12}+ \frac{2}{12}= \frac{11}{12}$

$\frac{11}{12} - \frac{3}{4}= \frac{11}{12}- \frac{9}{12}= \frac{2}{12}$

$\frac{11}{12} - \frac{1}{6}= \frac{11}{12}- \frac{2}{12}= \frac{9}{12}$

$\frac{1}{6} + \frac{3}{4}= \frac{2}{12}+ \frac{9}{12}= \frac{11}{12}$

Cập nhật: 07/09/2021

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